punkt o wspołżednych (-4, 1/8) nalezy do wykresu funkcji F(x) = a ^ (x +1). Rozwiaz nierownosc f(x) <= 8.
F(x) = a ^ (x +1)
1/8 = a^(-4 + 1)
1/8 = a^(-3)
2^(-3) = a^(-3)
a = 2
2^ (x +1) ≤ 8
2^(x + 1) ≤ 2^3
x + 1 ≤ 3
x ≤ 2
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F(x) = a ^ (x +1)
1/8 = a^(-4 + 1)
1/8 = a^(-3)
2^(-3) = a^(-3)
a = 2
2^ (x +1) ≤ 8
2^(x + 1) ≤ 2^3
x + 1 ≤ 3
x ≤ 2