Question

1. jika log 2 = p dan log 3 = q maka log 27/8 adalah?
2.(log 21 - log 210) (log 16 - log 1,6) =

mohon bantu ya ...!!!

Answer 1

1.
log 27/8 = log (3/2)^3 = 3 log (3/2)
3 (logg 3 - log 2) = 3(q-p) = 3q -3p

2.
(log 21 - log 210 )(log 16 - log 1,6)
(log 21/210)(log16/1,6)
(log 1/10)(log 10)
-1*1 = -1

Answer 2

1. log 27/8 = log 3³ - log 2³
= q³-p³
2. (log 21 - log 210) (log 16 - log 1,6) = (log 21/210) (log 16/16)
= log  . log 10
= -1 . 1
= -1

kalo salah minta maaf yah.