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x1, x2 - miejsca zerowe
Δ = 2500/49
x₁ = (-b-√delta)/(2a) = -3
x₂ = (-b+√delta)/(2a)= 7
5/7(x- (-3)) (x-7)
f(x)= 5/7(x+3)(x-7) - postać iloczynowa