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f(5) = -3/5 · 5 = - 3
f(10) = -3/5 · 10 = - 6
(5,-3) i (10,-6)
b) odcięta musi być wielokrotnością 7
f(7) = - 4/7 · 7 - 1 = - 4 - 1 = - 5
f(14) = -4/7 · 14 - 1 = - 8 - 1 = - 9
(7, - 5) i (14, - 9)