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1/12*360° = 30°
Zad.2.
d = 6 dm
l = 3km = 3000m = 30.000 dm
1. Obliczam obwód koła
O = π*d
O = π*6 dm
π = 22/7
O = (22/7)*6 dm = 132/7 dm
2. Obliczam ilość obrotów koła na długości 3 km
x = l : O
x = 30.000 dm : (132/7)dm
x = 30.000*(7/132)
x = 2500*7:11
x = 17500/11
x = 1590 i 10/11
x ≈ 1591 obrotów