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P₁=∏r1²
P¹=3,14*7²=3,14*49=153,86m²
P₂=3,14*r2²
P₂=3,14*28²=2461,76m²
Powierzchnia pod asfalt
P=2461,76-153,86=2307,9m²
P₁=πr₁²
P₁=²²/₇ * (7m)²
P₁=²²/₇*49m²
P₁= 154 m²
P₂=πr₂²
P₂= ²²/₇* (28m)²
P₂= ²²/₇* 784m²
P₂= 2464m²
P= 2464m²-154m²
P= 2310m²
Odp. Wokół ronda należy wylać 2310 m² asfaltu.