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maka jari2 ?
luas selimut tabung = 2 x π x r x t
r = luas / (2 x π x t)
= 528 / (2 x 22/7 x 12)
= 7 cm
2.
2. . r . 12
Lst . =2.r .12
528 .7/22 =2. r .12
168 = 2.r.12
r = 168 : 12 :2
r= 7