(-2,8)do potęgi6 x (3 i 4/7) do potęgi 6 = ?
(-2,8)^6 x (3 i 4/7)^6 = (-2,8 x 3 i 4/7)^6 =( -28/10 x 25/7)^6 = (-10)^6 = 1 000 000
(-2,8)^6 x (3 4/7)^6 =
=(-14/5 x 25/7)^6 =
= (-10)^6 =
= 1 000 000
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(-2,8)^6 x (3 i 4/7)^6 = (-2,8 x 3 i 4/7)^6 =( -28/10 x 25/7)^6 = (-10)^6 = 1 000 000
(-2,8)^6 x (3 4/7)^6 =
=(-14/5 x 25/7)^6 =
= (-10)^6 =
= 1 000 000