Zapisz w postaci potęgi liczby 3:
(1/9)^3*3-^5*27
____________ =
(1/7)-^2*3
Myślę, że to będzie tak:
(1/9)^3 * 3^-5 * 27 : (1/7)^-2 * 3 = (1/3)^6 * (1/3)^5 * 3^3 : 7^2 * 3^1
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Myślę, że to będzie tak:
(1/9)^3 * 3^-5 * 27 : (1/7)^-2 * 3 = (1/3)^6 * (1/3)^5 * 3^3 : 7^2 * 3^1