Question

MATMA ! ;(
PILNIE POTRYEBNE NA TERAZ ! :(

a) (⅗)⁸ : (0,6)⁶ - (4½)⁵ * (2/9)⁵
b) (2⅓)⁷ : (-7/3)⁸ + (2/7)³ * (1¾)²

Answer 1

a) (0,6)^8:(0,6)^6-(9/2)^5*(2/9)^5=(0,6)^(8-6) - 1^5=(0,6)^2 -1=0,36-1=0,64

 

b) (2⅓)⁷ : (-7/3)⁸ + (2/7)³ * (1¾)²=(7/3)^7:(-7/3)^8+(2/7)^3*(7/4)^2=

(7/3)^7:(7/3)^8*1+(2/7)*(2/7)^2*(7/4)^2= (7/3)^(7-8)*1+2/7*(2/7*7/4)=

(7/3)^-1*1+2/7*(1/2)^2=3/7+1/14=6/14+1/14=7/14=1/2=0,5