Question

zad 1

W miejse kropek wstaw brakujące czynniki:

...... (2x-1)= 6x-3

...... (4a +5b) = -8a - 10b

...... (-9+3x)= 9-3x

...... (- 2x- 3y)= 10x+15y

..... (x-y+3) = -4x+4y-12

..... (8m-n+1)= 40m+5n-5

zad2

Sprowadż do prostrzej postaci:

a) 3x(5y-6)-6(y-3x)-5y(3x+4)

b) 4a(3b-c)-(ab-4ac)-6b(2a-1/6a)

c) a- a (b-1)-(-b+a)-b(-a+1)

Prosze o pomoc!!!

dam NAJ!!!

;)

Answer 1

3 (2x-1)= 6x-3

2 (4a +5b) = -8a - 10b

-1 (-9+3x)= 9-3x

-5 (- 2x- 3y)= 10x+15y

-4 (x-y+3) = -4x+4y-12

5 (8m-n+1)= 40m+5n-5

 

a) 3x(5y-6)-6(y-3x)-5y(3x+4)=15xy - 18x -6y +18x - 15xy -20y =-26y

b) 4a(3b-c)-(ab-4ac)-6b(2a-1/6a)= 12ab - 4ac - ac + 4ac - 12ab + 1 ab= -ac + ab

c) a- a (b-1)-(-b+a)-b(-a+1)=a - ab - 1a - b - a - ab - 1b = -a - 2ab -2b

Answer 2

zad1.

3(2x-1)=6-3

2(4a+5b)=-8a-10b

-1(-9+3x)=9-3x

-5(-2x-3y)=10x+15y

-4(x+y+3)=-4x+4y-12

5(8m-n+1)=40m+5n-5

zad2.

a)3x(5y-6)-6(y+3x)-5y(3x+4)=15xy-18-6y+18x-15xy-20y=-26y

b)4a(3b-c)-(b-4ac)-6B(2a-1/6a)=12ab-4ac-ac+4ac-12ab+1ab=-ac+ab

c)a-a(b-1)-(-b+a)-b(-a+1)=a-ab-1a-b-a-ab-1b=-a-2ab-2b