mnożenie ulamków wymiernych
a)2/3x(-0,125)=
b)3 1/2x (-2 2/3)=
c) - 2/5x(-5/6)=
a)2/3x(-0,125)=-(2/3*0,125)=(-500/3000)= -5/30= - 1/6
b)3 1/2x (-2 2/3)=-(7/2*8/3)= -56/6= -28/3= -9 1/3
c) - 2/5x(-5/6)=10/30=3/10
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a)2/3x(-0,125)=-(2/3*0,125)=(-500/3000)= -5/30= - 1/6
b)3 1/2x (-2 2/3)=-(7/2*8/3)= -56/6= -28/3= -9 1/3
c) - 2/5x(-5/6)=10/30=3/10