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(3^4)^{x^2 + x} = 3^{-2}
3^{4x^2 + 4x} = 3^{-2}
4x^2 + 4x = -2 | / 4
x^2 + x + 1/2 = 0
Delta = 1^2 - 4 * 1 * (1/2) = 1 - 2 = -1
brak rozwiązań (x należy do zbioru pustego)
d) (1/8)^{5x-1} = (8^2)^{-7x+2}
8^{1 - 5x} = 8^{-14x+4}
1 - 5x = -14x + 4
9x = 3
x = 1/3