6(2a-6b+3c)
(3x-2y+9)*4
3(5x-8z-2)
-8(7n+9p+t)
3(b-5a)-2(3b+a)
(4x-7y-7)(-2)
-2(3a+1)+(4a-5)
5(2x+3y)-(x-2y)
prosze o rozwiązanie tych podunktów
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6(2a -6b +3c) = 12a -36b +18c
(3x -2y +9) *4 = 12x -8y +36
3(5x -8z -2) = 15x -24z -6
-8(7n +9p +1) = -56n -72p -8
3(b -5a) -2(3b +a) = 3b -15a -6b -2a = -17a -3b
(4x -7y -7) (-2)= -8x +14y +14
-2(3a +1) +(4a -5)= -6a -2 +4a -5 = -2a -7
5(2x +3y) - (x-2y) = 10x +15y -x +2y= 9x +17y
12a-36b+18c
12x-8y+36
15x-24z-6
-56n-72p-8t
3b-15a-6b-2a= -3b-17a
-8x+14y+14
-6a-2+4a-5= -2a-7
10x+15y-x+2y= 9x+17y
prosze