Question

Zadanie 29, str.30. / matematyka 2 gim . a) 2^a = 1/4 b) (1/3)^b = 27 c) (0,1)^c = 1000 d) (0,2)^d = 25 e) (-2)^e = -1/32 f)0,25^f = 16 g) 1000^g = 0,001^3 h) 25^-2 = (1/625)^h tylko prosze o dzialania jak do tego doszliscie ;)

Answer 1

a) 2^a = 1/4

(1/2)^{-a}=(1/2) ²

-a=2

a=-2 

b) (1/3)^b = 27

3^{-b}=3³

-b=3

b=-3 

c) (0,1)^c = 1000

(1/10)^c=10³

10^{-c}=10³

-c=3

c=-3 

d) (0,2)^d = 25

(1/5)^d=(1/5)⁻²

d=-2 

e) (-2)^e = -1/32

(-2)^e=(-2)⁻⁵

e=-5 

f)0,25^f = 16

(1/4)^f=(1/4)⁻²

f=-2 

g) 1000^g = 0,001^3

1000^g=(1000)⁻³

g=-3 

h) 25^-2 = (1/625)^h

(1/25)²=(1/25)^{2h}

2=2h

h=1

 

licze na naj