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Hambatan sebuah lampu
R = V²/P = 60²/90 = 40 Ω
Hambatan seri
Rs = R1 + R2 = 40 + 40 = 80 Ω
Setelah rangkaian diberi tegangan 40 V,
P = V²/R = 40²/80 = 20 W..<-- jawaban
p = V2 /r = 40kuadrat /80 =20 w