5+x+1=x do potgi 2 wsyzstko
[(5+x+1)=x]^2
(6+x)^2=x^2
36+12x+x^2=x^2
36+12x=0
12(3+x)=0/:12
3+x=0
x=-3
x=(-3)
(ten znaczek ^ oznacza do potegi 2)
prosze :)
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[(5+x+1)=x]^2
(6+x)^2=x^2
36+12x+x^2=x^2
36+12x=0
12(3+x)=0/:12
3+x=0
x=-3
[(5+x+1)=x]^2
(6+x)^2=x^2
36+12x+x^2=x^2
36+12x=0
12(3+x)=0/:12
3+x=0
x=(-3)
(ten znaczek ^ oznacza do potegi 2)
prosze :)