Question

1 1/5 x 1 2/3 x 1/7 + (1 1/7) do potęgi durgiej =

10 - 2 x ( 3 1/5 - 2 1/4 x 1/3) =

(7/3 - 5/12 + 1 1/2) : (2 3/4 - 5/6) =

(2 1/6 - 2/3) do potęgi drugiej - 2 1/5 =

Answer 1

1 1/5 x 1 2/3 x 1/7 + (1 1/7) do potęgi durgiej =

 

10 - 2 x ( 3 1/5 - 2 1/4 x 1/3) = 10 - 2 x (3 - 2 x ) = 10 - 2 x (3 - ) = 10 - 2 x 2 = 10 - 4 = 5

 

(7/3 - 5/12 + 1 1/2) : (2 3/4 - 5/6) = (28/12 - 5/12 + 18/12) : (33/12 - 10/12) = 41/12 : 23/12 = 41/12 x 12/23 (obie 12 skracaja sie przez 12) 41/23 = 1 18/23

 

(2 1/6 - 2/3) do potęgi drugiej - 2 1/5 = (13/6 - 4/6) - 2 1/5 = (169/36 - 16/36) - 2 1/5 = 153/36 - 11/5 = 51/12 - 11/5 = 510/120 - 264/120 = 246/120 = 2 6/20