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ze wzoru jedynkowego
sin²α + cos²α = 1
cos²α = 24/25
cosα = 2√6/5
tgα = sinα/cosα
tgα = 1/5 / 2√6 / 5 = 1/5 * 5/2√6 = 1 / 2√6 = √6/12
ctgα = 1/tgα = 1/ √6/12 = 12/√6 = 2√6
pzdr ;)