Przyprostokatna ma 8, przeciwprostokątna ma 10 , tg kąta ostrego wynosi: 5/3,5/4,3/4 czy 4/5
tga = b / a
a = 8 b = ? c = 10
a² + b² = c²
b² = c² - a²
b² = 10² - 8²
b² = 100 - 64
b² = 36
b = 6
tga = 6 / 8 = 3/4 ----- odpwoiedx
x - druga przyprostokątna
8²+x²=10²
64+x²=100
x²=36
x=6
tgα=6/8=3/4
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tga = b / a
a = 8 b = ? c = 10
a² + b² = c²
b² = c² - a²
b² = 10² - 8²
b² = 100 - 64
b² = 36
b = 6
tga = 6 / 8 = 3/4 ----- odpwoiedx
x - druga przyprostokątna
8²+x²=10²
64+x²=100
x²=36
x=6
tgα=6/8=3/4