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AC² = AB² + BC²
= (2√5)² + 4²
= 36
AC = 6 cm
maka AP = 1/3 × 6 = 2 cm ⇒ PC = 6 - 2 = 4 cm
Pada gambar ΔEPG,
EP² = AP² + AE²
= 2² + (4√3)²
= 52
EP = 2√13 cm
PG² = PC² + CG²
= 4² + (4√3)²
= 64
PG = 8 cm
EG = AC = 6 cm
Berdasarkan aturan Kosinus, maka
EG² = EP² + PG² - 2(EP)(PG)cosP
⇒ 6² = (2√13)² + 8² - 2(2√13)(8)cosP
⇒ 36 = 52 + 64 - 32√13cosP
⇒ 32√13cosP = 80
⇒ cosP = 80/(32√13)
⇒ cosP = 5/2√13
⇒ cosP = 5/2√13 × √13/√13
⇒ cosP = 5√13/26
⇒ cosP = (5/26)√13
Jawab : D
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