Question

50 poin kak, harus pake cara ya kak

Answer 1

Diket :
r = 8 cm

ditanya : PF->ACGE...?
jawab :

Titik P ditengah AB, tarik kebelakang, titik P ditengah CD.
• Buat titik tengah pula ditengah BC beri nama Q

PQ = √([r/2]^2 + [r/2]^2)
PQ = √([8/2]^2 + [8/2]^2)
PQ = √(4^2 + 4^2)
PQ = 4√2 cm

PG = √([r/2]^2 + r^2)
PG = √(4^2 + 8^2)
PG = √(16+64)
PG = √80
PG = 4√5 cm

• buat titik tengah di garis PQ, beri nama O

OG = √(PG^2 - PO^2)
OG = √([4√5]^2 - [PQ/2]^2)
OG = √(80 - [2√2]^2)
OG = √(80 - 8)
OG = √72
OG = 6√2 cm

•> tan PF->ACGE =
•> (PO)/(OG)
•> (2√2)/(6√2)
•> 2/6
•> 1/3 #B

Note :
• PO = OQ = (4√2)/2
~~~~~~~~~ = 2√2