sen = cateto opuesto / hipotenusa
3/5 = 20-x / x+2
5(20-x) = 3(x+2)
100-5x= 3x+6
94=8x
94/8= x
47/4 = x
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sen = cateto opuesto / hipotenusa
3/5 = 20-x / x+2
5(20-x) = 3(x+2)
100-5x= 3x+6
94=8x
94/8= x
47/4 = x