Jak to obliczyć?
7z + 4c - z - 3c , gdy z -2/7 a c -1/5
Proszę o pomoc : )
7z+4c-z-3c=7*(-2/7)+4*(-1/5)-(-2/7)-3*(-1,5)=-2-0,8+2/7+4,5=-2,8+2/7+4,5=-28/10+2/7+45/10=-196/70+20/70+315/70=139/70=1 i 69/70
7z + 4c - z - 3c = 6z + 1c = 6 x 2/7 + 1/5 = 12/7 + 1/5 = 60/35 + 7/35 = 67/35 = 1 i 32/35
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7z+4c-z-3c=7*(-2/7)+4*(-1/5)-(-2/7)-3*(-1,5)=-2-0,8+2/7+4,5=-2,8+2/7+4,5=-28/10+2/7+45/10=-196/70+20/70+315/70=139/70=1 i 69/70
7z + 4c - z - 3c = 6z + 1c = 6 x 2/7 + 1/5 = 12/7 + 1/5 = 60/35 + 7/35 = 67/35 = 1 i 32/35