Zapisz w postaci jednej potęgi, a następnie oblicz. W 3 (1) ³ · 4³ - (} · 4 ) ² − ( 3 ) ³

psiaki2002 @psiaki2002

June 2022 1 5 Report

Zapisz w postaci jednej potęgi, a następnie oblicz.
W
3
(1) ³ · 4³ - (} · 4 ) ² − ( 3 ) ³ - }
=
a) (4) ¹.204 =
b) 15³ . (²)³ =
18¹ = (18) 4 = 24 = 16
94
8) 3/5² =
h)
=
92
c) 24²-(1)² =
d) (3) 4.64
e) (§)³ - (§)³ =
1) (39)²-(²) ² -
2
i)
323
16
63
j)
=
183
k) 422: 62 =
1) 54:154 =

Plzz potrzebuje na jutro (DAJE NAJ)

basetla

$a) \ (\frac{1}{4})^{4}\cdot20^{4} =(\frac{1}{4}\cdot20)^{4} =(\frac{20}{4})^{4} = 5^{4} = 625\\\\b) \ 15^{3}\cdot(\frac{1}{5})^{3} =(15\cdot\frac{1}{5})^{3} = (\frac{15}{5})^{3} = 3^{3} = 27\\\\c) \ 24^{2}\cdot(\frac{1}{4})^{2} = (24\cdot\frac{1}{4})^{2} = (\frac{24}{4})^{2} = 6^{2}= 36\\\\d) \ (\frac{1}{3})^{4}\cdot6^{4} = (\frac{1}{3}\cdot6)^{4} = (\frac{6}{3})^{4} = 2^{4} = 16\\\\e) \ (\frac{8}{3})^{3}\cdot(\frac{5}{4})^{3} = (\frac{8}{3}\cdot\frac{5}{4})^{3} = (\frac{8}{4})^{3} = 2^{3} = 8$

$f) \ (\frac{36}{7})^{2}\cdot(\frac{7}{9})^{2} = (\frac{36}{7}\cdot\frac{7}{9})^{2} = (\frac{36}{9})^{2} = 4^{2} =16\\\\g) \ \frac{35^{2}}{7^{2}} = (\frac{35}{7})^{2} =5^{2} = 25\\\\h) \ \frac{63^{2}}{9^{2}} = (\frac{63}{9})^{2} = 7^{2} = 49\\\\i) \ \frac{32^{3}}{16^{3}} = (\frac{32}{16})^{2} = 2^{2} = 4$

$j) \ \frac{6^{3}}{18^{3}} = (\frac{6}{18})^{3}=(\frac{1}{3})^{3} = \frac{1}{27}\\\\k) \ 42^{2}:6^{2} = (42:6)^{2} = 7^{2} = 49\\\\l) \ 5^{4}:15^{4} = (5:15)^{4} = (\frac{1}{3})^{4} = \frac{1}{81}$