Question

Oblicz pole prostokąta o bokach a i b: a=6^3/5, b=2^2/5 * 3^7/5 Czy ktoś wytłumaczy jak to rozwiązać?

Answer 1

a = 6^3/5 = 2^3/5·3^3/5

 

b = 2^2/5 · 3^7/5

 

pole prostokata to:

P = a·b = 2^2/5·2^3/5 ·3^3/5·3^7/5 = 2^5/5·3^10/5 = 2^1·3^2 = 2·9=18

Answer 2

a = 6^3/5 = 2^3/5·3^3/5

b = 2^2/5 · 3^7/5

 

pole 

P = a·b = 2^2/5·2^3/5 ·3^3/5·3^7/5 = 2^5/5·3^10/5 = 2^1·3^2 = 2·9=18