oblicz wartość wyrażenia x^2 + y^2 dla: a) x= 20 i y= -21 b) x= 3/5 i y = 4/5 c) x= 0,5 i y= 1,2
daje naj
a) 20*2+(-21)*2=40-42=-2 (plus i minus daja minus)b)3/5*2+4/5*2=6/5+8/5=14/5=2i2/5c)0,5*2+1,2*2=1+2,4=3,4
a)
40^2+(-21)^2 = 1600 + 441 = 2041
b)
(3/5)^2 + (4/5)^2 = 9/25 + 16/25 = 1
c)
0,5^2 + 1,2^2 = 0,25 + 1,44 = 1,69
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
a) 20*2+(-21)*2=40-42=-2 (plus i minus daja minus)
b)3/5*2+4/5*2=6/5+8/5=14/5=2i2/5
c)0,5*2+1,2*2=1+2,4=3,4
a)
40^2+(-21)^2 = 1600 + 441 = 2041
b)
(3/5)^2 + (4/5)^2 = 9/25 + 16/25 = 1
c)
0,5^2 + 1,2^2 = 0,25 + 1,44 = 1,69