(4x do kwadratu - 3x) - (x + 0 1x do kwadratu) -( x do kwadratu - 0,1x )
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4x²-3x-x-0,1x²-x²+0,1x= 2,9x²-3,9x
(4x ² - 3x) - (x + 0 1x²) -( x² - 0,1x )=
=4x² -3x -x -0,1x²-x²+0,1x =
= 2,9x²-3,9x
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4x²-3x-x-0,1x²-x²+0,1x= 2,9x²-3,9x
(4x ² - 3x) - (x + 0 1x²) -( x² - 0,1x )=
=4x² -3x -x -0,1x²-x²+0,1x =
= 2,9x²-3,9x