Rozwiąż równania: b) 4[2(2x+3)+1]+2=5[3(4-x)-2]-4 d) (x-3) (x+4)-2(3x-2)=(x-4) do potęgi 2. h) x+3(2-x)/2=-1/6+ -3-x/3 i) -x-2/3-x-3/4=x-1
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b) 4[2(2x+3)+1]+2=5[3(4-x)-2]-4
4[4x+6+1]+2=5[12-3x-2]-4
4[4x+7]+2=5[10-3x]-4
16x+28+2=50-15x-4
16x+30=46-15x
31x=16/31
16
x= ___
31