Oblicz pole rombu o przekątnych
a) 0,03m i 12cm b) 4dm i 1,2m c) 1/4m i 0,4dm
pilne dam naj plissss
P = (1/2) e*f
================
a) P = (1/2) * 3 cm * 12 cm = 18 cm^2
======================================
b) P = (1/2)* 4 dm *12 dm = 24 dm^2
c) P = (1/2) * 25 cm * 4 cm = 50 cm^2
lub
P = (1/2)*2, 5 dm * 0,4 dm = 0,5 dm^2
====================================
a) p=(3*12):2
p=36:2
p=18cm^2
b)p=(40*120):2
p=4800:2
p=2400cm^2 ->24m^2
c)p=(0,25*4):2
p=1:2
p=0,5cm^2
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P = (1/2) e*f
================
a) P = (1/2) * 3 cm * 12 cm = 18 cm^2
======================================
b) P = (1/2)* 4 dm *12 dm = 24 dm^2
======================================
c) P = (1/2) * 25 cm * 4 cm = 50 cm^2
lub
P = (1/2)*2, 5 dm * 0,4 dm = 0,5 dm^2
====================================
a) p=(3*12):2
p=36:2
p=18cm^2
b)p=(40*120):2
p=4800:2
p=2400cm^2 ->24m^2
c)p=(0,25*4):2
p=1:2
p=0,5cm^2