4^log 2 [3] = [2^2]^log 2 [3] = 2^( 2*log 2 [3]) = 2^log 2[ 3^2] = 2^log 2 [9] = 9
log 16 [ 2] = 1 /( log 2 [ 16]) = 1/4
zatem
4^log 2 [3] + log 16 [ 2] = 9 + 1/4 = 9,25
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4^log 2 [3] = [2^2]^log 2 [3] = 2^( 2*log 2 [3]) = 2^log 2[ 3^2] = 2^log 2 [9] = 9
log 16 [ 2] = 1 /( log 2 [ 16]) = 1/4
zatem
4^log 2 [3] + log 16 [ 2] = 9 + 1/4 = 9,25
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