Rozwiąże mi to ktoś ? :D Z góry dzięki :)
1/2x-3/4[x-(4x+1)]=1-x+1/4
a) 1/2 x - 3/4 [ x - (4x +1)] = 1 -( x+ 1) / 4 / mnożymy obustronnie przez 4 2x - 3(x-4x-1)=4-(x+1) 2x-3(-3x-1)=4-x-1 2x+9x+3=3-x 11x+3=3-x 12x+3=3 12x=0 x=0
1/2x - 3/4 [x - (4x +1)] = 1 -(x+ 1) / *42x - 3(x-4x-1)=4-(x+1)2x-3(-3x-1)=4-x-12x+9x+x=3-312x=0 / : 12x=0
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a) 1/2 x - 3/4 [ x - (4x +1)] = 1 -( x+ 1) / 4 / mnożymy obustronnie przez 4
2x - 3(x-4x-1)=4-(x+1)
2x-3(-3x-1)=4-x-1
2x+9x+3=3-x
11x+3=3-x
12x+3=3
12x=0
x=0
1/2x - 3/4 [x - (4x +1)] = 1 -(x+ 1) / *4
2x - 3(x-4x-1)=4-(x+1)
2x-3(-3x-1)=4-x-1
2x+9x+x=3-3
12x=0 / : 12
x=0