Question

2 gimnazjum - ( 14str , 1 i 2 ćwiczenie ) ( Jak jest np. 1/2 to są ułamki )

1. Zapisz iloczyny w postaci jednej potęgi i oblicz:

a) 2³ * 2³

b) (-2)² * (-2)³

c) 3² * 3²

d) (-3) * (-3)²

e) (-10)² * (-10)³ * (-10)

f) (-1)⁵ * (-1)² * (-1)⁴

g) (1/2)³ * (1/2) * (1/2)²

h) (-0,1) * (-0,1)² * (-0,1)²

i) (0,2)² * (0,2) * (0,2)²

2. Przedstaw w postaci jednej potęgi:

a) (-5)⁶ * (-5)⁵

b) (6/7)⁴ * (6/7)⁵

c) (-1,3)⁶ * (-1,3)² * (-1,3)⁵

d) (-0,75)⁵ * (-3/4)⁶

e) (1,25)⁷ * (5/4)⁸

f) x⁴ * x⁹ * x

g) (-3xy)⁴ * (-3xy)⁵ * (-3xy)²

h) (7 - b)⁵ * (7 - b)² * (7 -b)

i) (a + b)³ * (a + b)⁶ * (a + b)²

Answer 1

. Zapisz iloczyny w postaci jednej potęgi i oblicz:

a) 2³ * 2³ =2⁶ = 64

b) (-2)² * (-2)³ =(-2) ⁵ = -32

c) 3² * 3² =3⁴ = 81

d) (-3) * (-3)² =(-3)³ = -27

e) (-10)² * (-10)³ * (-10) = (-10)⁶=1000000

f) (-1)⁵ * (-1)² * (-1)⁴ =(-1)¹¹ = -1

g) (1/2)³ * (1/2) * (1/2)²=(1/2) ⁶ = 1/64

h) (-0,1) * (-0,1)² * (-0,1)² =(-0,1) ⁵ = (-1/10)⁵ = -1/100000

i) (0,2)² * (0,2) * (0,2)² =(0,2)⁵=  (2/10)⁵ = 32/100000

 

2. Przedstaw w postaci jednej potęgi:

a) (-5)⁶ * (-5)⁵ = (-5)¹¹

b) (6/7)⁴ * (6/7)⁵ = (6/7)⁹

c) (-1,3)⁶ * (-1,3)² * (-1,3)⁵ =(-1,3)¹³

d) (-0,75)⁵ * (-3/4)⁶ = (-3/4)¹¹

e) (1,25)⁷ * (5/4)⁸ = (4/5)¹⁵

f) x⁴ * x⁹ * x = x¹⁴

g) (-3xy)⁴ * (-3xy)⁵ * (-3xy)² =(-3xy)¹¹

h) (7 - b)⁵ * (7 - b)² * (7 -b) = (7-b)⁸

i) (a + b)³ * (a + b)⁶ * (a + b)² =(a+b)¹¹