Hej pomóżcie ! 1.Zapisz w jak najprostszej postaci wyrażenia: a)-4y-(-7y-3z+1)= b)6ab-(5a-4b+6ab)= c)-3xy-(-2x+5y-3xy)= d)(4z-3)-(5z+2yz-4)+2yz= e)4x+(-3x+2)-2x+1= f)3+(2x-1)+(4-x)= g)(2a-b)+(3a-2b) h)4xy+(3-4xy)= i)24a+b-(4a+2b)= j)(2ab-3)-(2+2ab)= k)-5b-2a+(3a-2b)= l)-(3+2ab)-4ab= m)(0.2a-3b)-(-0.8+3b)= n)1/4x-(0.2-1 i 1/4x)= o)4 i 2/3a-(3/4a+1)=
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a)-4y-(-7y-3z+1)= -4y+7y+3z-1=3y+3z+1
b)6ab-(5a-4b+6ab)=6ab-5a+4b-6ab=-5a+4b
c)-3xy-(-2x+5y-3xy)=-3xy+2x-5y+3xy=2x-5y
d)(4z-3)-(5z+2yz-4)+2yz=4z-3-5z-2yz+4+2yz=-z+1
e)4x+(-3x+2)-2x+1=4x-3x+2-2x+1=-x+3
f)3+(2x-1)+(4-x)=3+2x-1+4-x=x+6
g)(2a-b)+(3a-2b)=2a-b+3a-2b=5a-3b
h)4xy+(3-4xy)= 4xy+3-4xy=3
i)24a+b-(4a+2b)= 24a+b-4a-2b=20a-b
j)(2ab-3)-(2+2ab)=2ab-3-2-2ab= -5
k)-5b-2a+(3a-2b)=-5b-2a+3a-2b= -7b+a
l)-(3+2ab)-4ab=-3-2ab-4ab=-3-6ab
m)(0.2a-3b)-(-0.8+3b)=0,2a-3b+0,8-3b=0,2a-6b+0,8
n)1/4x-(0.2-1 i 1/4x)=0,25x-0,2+1,25x= 1,5x-0,2
o)4 i 2/3a-(3/4a+1)= 4 2/3a- 3/4a-1= -1 + 3 11/12a
Pozdrawiam ;D