rozwiąż równania : 3a+1 3/4=2 1/5, 1 2/3 -5c=1 1/4.1/2p:1 3/4=8 bardzo proszę
3a +1i3/4 = 2i1/5
3a + 7/4 = 11/5 /*20
60a + 35 = 44
60a = 44 - 35
60a = 9 /:60
a = 3/20
1i2/3 -5c = 1i1/4
- 5c = 1 i1/4- 1i2/3
-5c= 1 i3/12 - 1i8/12
-5c = -5/12 :(-5)
c = 5/12 * 1/5
c = 1/12 * 1/1
c = 1/12
1/2p : 1i3/4 = 8
1/2p : 7/4 = 8
1/2p * 4/7 =8
4/14p = 8 /:4/14
p = 8 * 14/4
p = 2 *14/1
p = 28
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3a +1i3/4 = 2i1/5
3a + 7/4 = 11/5 /*20
60a + 35 = 44
60a = 44 - 35
60a = 9 /:60
a = 3/20
1i2/3 -5c = 1i1/4
- 5c = 1 i1/4- 1i2/3
-5c= 1 i3/12 - 1i8/12
-5c = -5/12 :(-5)
c = 5/12 * 1/5
c = 1/12 * 1/1
c = 1/12
1/2p : 1i3/4 = 8
1/2p : 7/4 = 8
1/2p * 4/7 =8
4/14p = 8 /:4/14
p = 8 * 14/4
p = 2 *14/1
p = 28