zad.3./47
d) 3 ∛7 * 2(∛7) ² =
e) 5(∛-6) ² * 4∛-6 =
f) (-7 ∛-2) ² * ∛-2 =
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a = 42
b = -120
c = 14
d) 3∛7 · 2(∛7)²= 6·(∛7)³= 6·7=42
e) 5(∛-6)² · 4∛-6 = 20(∛-6)³ = 20·(-6) = -120
f) (-7 ∛-2)² · ∛-2 = 49· (∛-2)²· ∛-2 = 49 ·(∛-2)³ = 49·(-2) = -98