Zadanie 4.6 /46, prosto do matury. Rozwiąż nierówność:
a) (x+1)² < (x-1)²
b) (3x+1)² ≤ 8x-(2-3x)(2+3x)
c) (x+1)²-5(x-2) ≥ (x+ √13)(x-√13 )
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a) (x+1)² < (x-1)²
x²+2x+1 < x² - 2x + 1
4x<0
x < 0
b) (3x+1)² ≤ 8x-(2-3x)(2+3x)
9x²+6x+1 ≤ 8x - 4 + 9x²
2x ≥ 5
x ≥ 2,5
c) (x+1)² -5(x-2) ≥ (x+ √13)(x-√13)
x²+2x+1 -5x+10 ≥ x² - 13
-3x≥-14
x≤14/3