Question

Zapisz w postaci jednej potęgi.
4^3*4^5=
(5^4)^3=
(6^2)^4=
7^6/7^4=
(-9)^15:(-9)^13=
16^3:16^3=
(5/3)^9*(5/3)^2=
((-4)^3)^5=
3^9*3=
(10^4)^5=
(-4)^8/(-4)^5=
Błagam na teraz jest to zadanie 1 str 32 ćwiczenie
Matematyka na czasie! Błagam na teraz daje naj
Ten znak ^ to do potęgi

Answer 1

4^3*4^5=4^{8}
(5^4)^3=5^12
(6^2)^4=6^8
7^6/7^4=7^2
(-9)^15:(-9)^13=9^2
16^3:16^3=16^0=1
(5/3)^9*(5/3)^2=(5/3)^11
((-4)^3)^5=(-4)^15
3^9*3=3^10
(10^4)^5=10^{20}
(-4)^8/(-4)^5=(-4)^3

Answer 2

4^3*4^5= 4^3+5=4^8
(5^4)^3=5^4*3=5^12
(6^2)^4=6^2*4=6^8
7^6/7^4=7^6-4=7^2
(-9)^15:(-9)^13=(-9)^15-13=(-9)^2
16^3:16^3=16^3-2=16^1
(5/3)^9*(5/3)^2=(5/3)^9+2=(5/3)^11
((-4)^3)^5=(-4)^3*5=(-14)^15
3^9*3=3^9+1=3^10
(10^4)^5=10^4*5=20
(-4)^8/(-4)^5=(-4)^8-5=(-4)^3

:)