Diketahui 2log5= x dan 2log3= y. nilai 2log300^3/4=.... Question from @iimdwi

October 2018 2 2K Report

Diketahui 2log5= x dan 2log3= y. nilai 2log300^3/4=.....

izharulhaq78 $^2log5=x \\ ^2log3=y \\ \\ ^2log300^{ \frac{3}{4}}=?$

$^2log300^{ \frac{3}{4}} \\ \frac{3}{4}(^2log300) \\\frac{3}{4}(^2log5(3)(20)) \\ \frac{3}{4}(^2log5+^2log3+^2log20)\\\frac{3}{4}(^2log5+^2log3+^2log4(5)) \\ \frac{3}{4}(^2log5+^2log3+^2log4+^2log5) \\ \frac{3}{4}(x+y+2+x) \\ \frac{3}{4}(2x+y+2) \\\frac{3(2x+y+2) }{4} \\\frac{6x+3y+6 }{4}$

8 votes Thanks 8

iimdwi itu pangkat 3/4 nya langsung di gituin aja kah? gak perlu di balik gitu kah?? sorry rada bingung

iimdwi oh... ya dah ngerti

NewBrainly100 cerdas :D

anisamurni $2log5=x, 2log3=y$
$2log300^ \frac{3}{4}$
$\frac{3}{4}2log300$
$\frac{3}{4}( \frac{log300}{log2} )$
$\frac{3}{4} ( \frac{log5^2.log2^2.log3}{log2} )$
$\frac{3}{4} ( \frac{2log5^2+2log2^2+2log3}{2log2} )$
$\frac{3}{4} ( \frac{2.2log5+2.2log2+2log3}{2log2})$
$\frac{3}{4} (2x+2+y)$
$\frac{6x+3y+6}{4}$

3 votes Thanks 4

iimdwi okay makasih pertologannya

anisamurni sama2 :)

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