Question

oblicz, pamiętając o kolejności wykonywania działań: a) [( 1 1/2 )do potęgi 2 - 1 3/5 : 1 1/3] :21 b)[(1 1/2)do potęgi 2 - 1 3/4 x 1 1/5] : 3

zad .2 oblicz 2-1 1/4

Answer 1

a) [(1i1/2)^2 -1i3/5 : 1i1/3] :21 =  [(3/2)^2 - 8/5:4/3] :21= [9/4 -8/5*3/4]:21 =

= [9/4 -2/5*3/1]:21= [9/4 - 6/5]: 21= [2i1/4-1i1/5]:21= =  [2i 5/20- 1 i4/20]:21=

= 1 i1/20 :21 = 21/20 : 21/1 = 21/20 * 1/21= 1/20 * 1/1 = 1/20

 

b) [(1i1/2)^2 - 1i3/4 * 1i1/5]:3 = [(3/2)^2 - 7/4* 6/5] :3 = [9/4 - 7/2*3/5]:3 =   

= [9/4 - 21/10] :3= [2i1/4 - 2i1/10] :3= [2i5/20-2i2/20]:3=3/20*1/3=1/20*1/1= 1/20

 

Zad.2

2 - 1 i 1/4 = 1 i 4/4  - 1 i1/4 = 3/4

Answer 2

a)[(1½)² -1³/₅ :1⅓] :21=[(3/2)² -8/5 : 4/3] :21=[9/4 -8/5 ·3/4 ]:21=[9/4-6/5]:21

= [45/20 - 24/20]:21=21/20 :21 =21/20 · 1/21  = 1/20

b)[(1½)² -1¾ ·1¹/₅]:3=[(3/2)² -7/4 ·6/5]:3 =[9/4 -21/10 ]:3=[45/20 -42/20]:3=

3/20 :3 =3/20 · 1/3 =20/1 =20 =1/20

b)2- 1¼=8/4  -5/4 = 3/4