prosze o pomoc
x=3-2√5
y=2+3√5
x/y
wynik musi wyjsc
-36 +13√5 /41
dam naj
y/x = (3-2√5)/(2+3√5) · (2-3√5)/(2-3√5) = [(3-2√5)(2-3√5)]/(4-45) = (6-9√5-4√5+30)/(-41) =
= (-36+13√5)/41
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y/x = (3-2√5)/(2+3√5) · (2-3√5)/(2-3√5) = [(3-2√5)(2-3√5)]/(4-45) = (6-9√5-4√5+30)/(-41) =
= (-36+13√5)/41