Question

Rozwiąż równania dowolną metodą.
b)
(2x - 1)/5 + (3y - 2)/4 = 2
(3x + 1)/5 - (3y + 2)/4 = 0
c)
(3x - 2y)/5 + (5x - 3y)/3 = x +1
(2x - 3y)/3 + (4x - 3y)/2 = y +1
d)
(x+1)/3 - (y + 2)/4 = 2(x - y)/5
(x-3)/4 - (y - 3)/3 = 2y - x
e)
10(y + 2) + 3(x - 5) = x - 5
25(y + 2) = 3(x - 5) = - 10
f)
2(2x - y) + 3(x + 3y) = 42
5(x + 3y) - 8(2x - y) = - 32
g)
(x + 2y)/4 - ( x - 1/3 y) = 1 + y
(y + 3)/6 + (2 - x)/8 = 3/2
h)
11/20 y - 0,8 (1/4 x + 2,5) = 2, 1/2
(6x - 0,3y)/2 - 1, 1/2 = 2(1 + x)
i)
y/2 + x/4 - 1/5 (x + 2) = 1,1
x - 2y + 4 = x/2 + 3/4 (y - 0,5)

Answer 1

B)
(2x - 1)/5 + (3y - 2)/4 = 2 II*20
8x-4+15y-10=2
-4-10-2=-8x-15y
-16=-8x-15y

(3x + 1)/5 - (3y + 2)/4 = 0
12x+4-15y+10=0
12x-15y=-4-10+0
12x-15y=-14