Rozwiąż układ równań{ y/2 + x/4 - 1/5 (x+2) = 1,1{ x - 2y + 4 = x/2 + 3/4 (y-0,5)
y/2 + x/4 - 1/5(x+2) =1,1/*20
x-2y +4 = x/2 + 3/4(y-0,5)/*4
10y+5x-4(x+2)=22
4x-8y+16=2x+3(y-0,5)
10y+5x-4x-8=22
4x-8y+16=2x+3y-4,5
x+10y=30
2x-5y=11,5/*2
x+10y=30= 10y=40,6
4x-10y=23 y=4,06
5x=53
x=10,6
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Pewnosci nie mam ale to z zeszytu brata :D
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y/2 + x/4 - 1/5(x+2) =1,1/*20
x-2y +4 = x/2 + 3/4(y-0,5)/*4
10y+5x-4(x+2)=22
4x-8y+16=2x+3(y-0,5)
10y+5x-4x-8=22
4x-8y+16=2x+3y-4,5
x+10y=30
2x-5y=11,5/*2
x+10y=30= 10y=40,6
4x-10y=23 y=4,06
5x=53
x=10,6
--------------------------
Pewnosci nie mam ale to z zeszytu brata :D