Question

KERJAKAN DENGAN CARANYA.

nyatakan bilangan berikut kepangkat positif.

1. 3^-4
2. 3 x 5^-2
3. a^-3
4. 4/b^-6
5. 1/2 a^-2
6. 1/5b^-4
7. 2^-3 x 2^2
8. 3^-4 : 3^2
9. (a^3 x a^2) : a^12
10. (b^-2)^3 : b^-1
11. (1/y-1)^2 x (y^-3)^4
12. p^-3 x q^2 x 5^-4
13. 3x^2y^-3
14. p^-1 q r^-1
15. 1/4 x^2 y^-3 2^-1

Answer 1

1. caranya dibalik mas, jadinya per, = 1/3^4
2. 3 x 5^-2 = 3/5^2
3. a^-3 = 1/a^3
4. 4/b^-6 = 4 x b^6
5. 1/2 a^-2 = 1/2 / a^2
6. 1/5 b^-4 = 1/5 / b^4
7. jika dikali pertama hasilnya 2^-1 = 1/2
8. 3^-4 / 3^2 = 3^-6= 1/3^6
9. hasil kali 1 = a^5/a^12 = a^-7 = 1/a^7
10. b^-6/b^-1 = b^-5 = 1/b^5
11. hasil kali 1 = 1/y^2-1 x y^-12, = 1/y^14-1
12. 1/p^3 x q^2 x 1/5^4
13. 3x^2 x 1/y^3
14. 1/px q x 1/r
15. 1/4 x^2 1/y^3 x 1/2

Answer 2

1. Kalo ini mas tinggal jadi pecahan aja ya 1/3^4
2. 3 x 5^-2 = 3/5^2
3. a^-3 = 1/a^3
4. 4/b^-6 = 4 x b^6
5. 1/2 a^-2 = 1/2 / a^2
6. 1/5 b^-4 = 1/5 / b^4
7. 2^-3 x 2^2 = 2^-1 = 1/2
8. 3^-4 / 3^2 = 3^-6= 1/3^6
9. (a^3 x 2^2 = a^5/a^12 = a^-7 = 1/a^7
10. b^-6/b^-1 = b^-5 = 1/b^5
11.  1/y^2-1 x y^-12, = 1/y^14-1
12. 1/p^3 x q^2 x 1/5^4
13. 3x^2 x 1/y^3
14. 1/px q x 1/r
15. 1/4 x^2 1/y^3 x 1/2