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2cos{-(x-π/4)}=√2 wiemy, że cosx = cos(-x) więc
2cos(x-π/4)=√2 I:2
cos(x-π/4) = √2/2
x-π/4=π/4+2kπ ∨ x-π/4=-π/4+2kπ ( k∈C )
x=π/4+π/4 +2kπ x=-π/4+π/4+2kπ
x=π/2+2kπ , k∈C ∨ x=2kπ , k∈C