Odpowiedź:
a1+a2+a3=3
a1=a1+0r
a2=a1+1r
a3=a1+2r
a1+a1+r+a1+2r=3
3a1+3r=3||:3
a1+1r=1
a2=1 musi być naturalna dodatnia
a1=1
a3=1
a1=1+5=6
a2=1+3=4
a3=1+3=4
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Odpowiedź:
a1+a2+a3=3
a1=a1+0r
a2=a1+1r
a3=a1+2r
a1+a1+r+a1+2r=3
3a1+3r=3||:3
a1+1r=1
a2=1 musi być naturalna dodatnia
a1=1
a3=1
a1=1+5=6
a2=1+3=4
a3=1+3=4