Pole powierzchni kuli wynosi 9/4 π .Oblicz objętość tej kuli.
P=
V=
Z: R>0
P=4πr²
9/4π=4πr²
9/4=4r² |*4
9=16r²
r²=9/16
r=¾
V=4/3πr³
V=4/3π*(¾)³=4/3π*27/64 = 9/16π
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P=
V=
Z: R>0
P=4πr²
9/4π=4πr²
9/4=4r² |*4
9=16r²
r²=9/16
r=¾
V=4/3πr³
V=4/3π*(¾)³=4/3π*27/64 = 9/16π