Question

Mohon bantuannya ya kak^^

Two charges, +2q and +q, are separated by a distance d. If a negative charged -Q is placed in the middle, located at d/4 near to the q charge, how is the resultant forve applied on the third charge?
a. 0
b. to the left towards 2q
c. to the right towards q
d. perpendicular in to the page..

Answer 1

F1 = K2Q(Q2)/(3/4d)^2 = 32/9 Kqq2/d^2 N
F2= K Q(Q2)/(1/4d)^2 = 16 Kqq2/d^2 N

F1:F2 = 32/9 : 16

F2 > F1 (move towards q)
answer c