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zad1)O=120
1 bok=a
2 bok =¼a
120=2·a+2·¼a
120=2a+½a
120=2½a
a=120:2,5
a=48
to drugi bok ¼·48=12cm
Pole prostokta P=ab=48·12=576cm²
zad2 O=28cm
1 bok =a
drugi bok =3/4a
28=2a+2·¾a
28=2a+1,5a
28=3,5a /:3,5
a=8cm
to drugi bok ¾·8=6cm
przekatna prostokta z pitagorasa
8²+6²=d²
64+36=d²
d=√100=10 cm --->odpowiedz