Oblicz pamiętając o kolejności wykonywania działań: a) (2 i 2/3x 7/8-1 i 1/2):4/9 b) 5 i 1/6:[12x (1 i 5/6+3/4] Daje najj
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a) (2 i2/3 * 7/8 - 1 i 1/2) : 4/9 =( 8/3 *7/8-1i1/2):4/9 = (1/3 * 7/1 - 1 i1/2): 4/9 =
= (7/3 -3/2):4/9=(14/6 - 9/6) :4/9= 5/6 * 9/4 = 5/2 * 3/4 = 15/8 = 1 i 7/8
b) 5i1/6 :[12 *(1i5/6 + 3/4) = 31/6 :[12*( 1 i 10/12 +9/12)] = 31/6:[12*(1i19/12)]=
= 31/6 : [12*31/12]= 31/6:(1*31/1] = 31/6 :31 = 31/6*1/31 = 1/6 *1 = 1/6
a)
b)